Truss Systems

A truss is an assemblage of slender straight members connected at joints, loaded only at joints, so each member is a two-force member carrying only axial tension (positive, elongates) or compression (negative, shortens). This makes trusses efficient for long spans with minimal bending. Ideal truss assumptions: 1) members connected by frictionless pins, 2) loads and reactions applied only at joints, 3) members straight and centroidal axes concurrent at joint, 4) self-weight negligible or lumped at joints. Real gusset plates introduce secondary moments, but primary analysis remains axial. Static determinacy (planar, simple truss): m + r = 2j for externally + internally determinate, where m = members, r = reaction components (3 for simply supported), j = joints. Internally, simple truss built from triangle satisfies m = 2j - 3. If m < 2j-3 → mechanism (unstable), m = 2j-3 → internally determinate, m > 2j-3 → internally indeterminate to (m - (2j-3)) degrees. Analysis principles: Method of joints: equilibrium at each joint ΣFx=0, ΣFy=0 (2 equations per joint). Start at joint with ≤2 unknowns. Method of sections: cut through ≤3 unknown members, apply ΣFx=0, ΣFy=0, ΣM=0 to one side - efficient for specific members. Sign convention: tension pulls away from joint, compression pushes into joint. Zero-force members: Rule 1: If only two non-collinear members meet at unloaded joint, both are zero-force. Rule 2: If three members meet at unloaded joint and two are collinear, third is zero-force. Rule 3: If two collinear members plus external load perpendicular to them, zero-force does not apply. Zero-force members provide stability during erection and brace compression chords against buckling. Limitations: Analysis assumes small deflections, elastic, and that buckling of compression members (Euler Fcr = π²EI/(KL)²) is checked separately - truss analysis gives force, not capacity. Joint rigidity and eccentricities cause secondary bending in real structures.

Governing FormulaJoint equilibrium: ΣFx = 0, ΣFy = 0 at each joint Section equilibrium: ΣFx = 0, ΣFy = 0, ΣM = 0 Determinacy: m = 2j - 3 (simple, internally determinate), m + r = 2j (with r=3) Zero-force: 2 non-collinear at unloaded joint → both F=0 3 members, 2 collinear, unloaded → non-collinear F=0 Force sign: T >0 tension (member pulls joint), C <0 compression 3-4-5 truss: For vertical load P at top, diagonal force = ±P·(hypotenuse/vertical) depending on geometry

Knowledge Check

10 Questions

1.What type of force does an ideal truss member primarily carry?

2.In a truss, what is the method of joints used for?

3.A simple planar truss has 10 joints and 18 members (simply supported, r=3). Is it internally statically determinate?

4.What is a zero-force member in a truss?

5.In the method of sections, what is cut to analyze a truss?

6.A 3-4-5 triangle truss has a 100 N vertical load at the top joint. The diagonal (5-unit hypotenuse) meeting the vertical (4-unit) - what is approximate force? Tension positive.

7.Which condition must be satisfied for an internally statically determinate simple planar truss?

8.Which is NOT a standard assumption in ideal truss analysis?

9.A truss member in tension will:

10.If two non-collinear members meet at a joint with no external load or reaction, what can be said?