Confidence Intervals

A confidence interval (CI) is an interval estimate for a population parameter constructed so that, under repeated random sampling, a specified proportion (1-α) of intervals will contain the true parameter. It solves the problem that a point estimate x̄ alone gives no measure of precision. Principle: x̄ varies by Standard Error SE = σ/√n (or s/√n when σ unknown). By CLT, for random independent samples, x̄ ≈ Normal(μ, SE²) if population is normal or n large enough. The CI is point estimate ± critical value × SE. For mean, σ known: x̄ ± z_{α/2}·σ/√n. σ unknown: x̄ ± t_{α/2, n-1}·s/√n, where t accounts for extra uncertainty in s, with df = n-1. As n grows, t → z. For proportion p̂: p̂ ± z_{α/2}·√[p̂(1-p̂)/n]. Width depends on: confidence level (1-α) via z or t, variability σ/s, and sample size n via 1/√n. Higher confidence → larger critical value → wider interval. Larger n → narrower interval. Assumptions: random sample, independent observations, n < 10% of population or with correction, approximate normality of x̄ (check n≥30 or population normal, no severe skew/outliers for t). For proportion, need n·p̂ ≥5 and n·(1-p̂) ≥5. Interpretation: A 95% CI does not mean 95% probability that this specific interval contains μ, nor that 95% of data lie in it. It means the procedure has 95% long-run coverage. CI is not a prediction interval for individual observations and is invalid if assumptions fail or bias exists.

Governing FormulaStandard Error (mean, σ known): SE = σ / √n Standard Error (mean, σ unknown): SE = s / √n CI mean, σ known: x̄ ± z_{α/2} · SE CI mean, σ unknown: x̄ ± t_{α/2, n-1} · SE, df = n-1 Margin of Error: ME = critical · SE CI proportion: p̂ ± z_{α/2} · √[p̂(1-p̂)/n] Critical values: 90% z=1.645, 95% z=1.96, 99% z=2.576 Width ∝ 1/√n

Knowledge Check

10 Questions

1.A sample of 36 students has a mean score of 75 with a population standard deviation of 12. What is the 95% confidence interval for the population mean? (Z = 1.96)

2.What is the critical Z-value for a 90% confidence interval?

3.When should the t-distribution be used instead of the normal distribution for confidence intervals?

4.As the sample size increases, the width of the confidence interval:

5.A sample has mean 50, standard deviation 10, and size 25. What is the 95% confidence interval using t-distribution? (t_0.025, 24 ≈ 2.064)

6.A 99% confidence interval is wider than a 95% confidence interval because:

7.What is the margin of error in a confidence interval?

8.A sample of 100 people has a mean height of 170 cm and standard deviation of 10 cm. What is the 95% confidence interval? (Z = 1.96)

9.The confidence level of 95% means that:

10.What is the critical t-value for a 95% confidence interval with degrees of freedom = 20? (Approximate)